H_(2(g)) + I_(2(g)) hArr 2HI in this equilibrium if H_2 is added than state the direction of reaction and explain it with help of Q_c.

H_(2(g)) + I_(2(g)) hArr 2HI in this equilibrium if H_2 is added than

1.	H_(2(g)) + I_(2(g)) hArr 2HI in this equilibrium if H_2 is added than state the direction of reaction and explain it with help of Q_c.
Answer» SOLUTION :`Q_c=[HI]^2/([H_2][I_2])` and `K_c=[HI]^2/([H_2][I_2])` As `H_2` is added it react with `I_2` So in EQUATION of `Q_c, H_2` and `I_2` increase so `Q_c` decreases. So the value of `Q_c lt K_c` Hence, reaction PROCEED in FORWARD direction and new equilibrium is attain.