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`H_(2)O_(2)` can be produced by the ammonium hydrogen sulphate. Reactions occuring in electrolytic cell, `NH_(4)HSO_(4)rarrNH_(4)^(-)+2e^(-)` (Anode) `2SO_(4)^(2-)rarrS_(2)O_(8)^(2-)+2e^(-)` `2H^(+)+2e^(-)rarrH_(2)` (Cathode) Hydrolysis of ammonium persulphate: `(NH_(4))_(2)S_(2)O_(8)+2H_(2)Orarr2NH_(4)HSO_(4)+H_(2)O_(2)` Assume 100% yield of hydrolysis reaction. How many "mole"s of electrons are to be passed in order to produce enough `H_(2)O_(2)` which when reacted with excess of KI then liberated iodine required 100 mL of centimolar hypo solution.A. `10^(-1)`B. `10^(-2)`C. `10^(-3)`D. `5xx10^(-4)`

Answer» Correct Answer - C


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