H_(2)O_(2) is ''5.6 volume '' then

1.	H_(2)O_(2) is ''5.6 volume '' then
Answer» It is 1.7% WEIGHT by volume It is 1N It is 1 M It is `5.6M` SOLUTION :`5.6 Vol to 1N to 0.5 M to 1.7 ((W)/(V))%`

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