H_(2)O_(2) is reduced rapidlly by Sn^(2+) to give H_(2)O and Sn^(+)H_(2)O_(2) is decomposed slowly at room temperature so yield O_(2) and H_(2)O. 136g of % by mass of H_(2)O in water treated with 100 mL 3 M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are 2H^(o+)+H_(2)O_(2)+Sn^(2+) to Sn^(2+)+2H_(2)O: 2H_(2)O+O_(2) The valume strength of H_(2)O_(2) left after reacting with Sn^(2+) is

H_(2)O_(2) is reduced rapidlly by Sn^(2+) to give H_(2)O and Sn^(+)H_(

1.	H_(2)O_(2) is reduced rapidlly by Sn^(2+) to give H_(2)O and Sn^(+)H_(2)O_(2) is decomposed slowly at room temperature so yield O_(2) and H_(2)O. 136g of % by mass of H_(2)O in water treated with 100 mL 3 M Sn^(2+) and then a mixture is allowed to stand until no further reaction occurs. The reactions involved are 2H^(o+)+H_(2)O_(2)+Sn^(2+) to Sn^(2+)+2H_(2)O: 2H_(2)O+O_(2) The valume strength of H_(2)O_(2) left after reacting with Sn^(2+) is
Answer» `1.12V` `11.2V` `2.24V` `22.4V` Solution :Intial no.of GEW.s of `H_(2)O_(2)=(13.6)/(17)=0.8` no.of GEW.s of `Sn^(+2)=6xx0.1=0.6` no.of GEW.s of `H_(2)O_(2)` left over `=0.2` no.of GEW.s of `H_(2)O_(2)` consumed `=0.6` no.of `H_(2)O_(2)` left `=0.2xx(1000)/(100)2N` VOL strength `=11.2`