1.

`H_(2)O` can be oxidised toA. `H_(2)` and `O_(2)`B. `O_(2)`C. `OH^(-)`D. `O^(2-)`

Answer» Correct Answer - B
`underset(+1)underset(uarr)(2H_(2))underset(-2)underset(uarr)(O) rarr underset(0)underset(uarr)(2H_(2))+underset(0)underset(uarr)(O_(2))`
`H` is reduced to `H_(2)` and `O` is oxidised to `O_(2)`.


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