H_(2)O_((g))rarrH_((g))+OH_((g))DeltaH=x_(1), OH_((g))rarrH_((g))+O_((g))DeltaH=x_(2) Based on these value, BE of O-H bond is

H_(2)O_((g))rarrH_((g))+OH_((g))DeltaH=x_(1), OH_((g))rarrH_((g))+O_(

1.	H_(2)O_((g))rarrH_((g))+OH_((g))DeltaH=x_(1), OH_((g))rarrH_((g))+O_((g))DeltaH=x_(2) Based on these value, BE of O-H bond is
Answer» `(x_(1)+x_(2))/(2)` `x_(1)+x_(2)` `(x_(1)-x_(2))/(2)` `2(x_(1)+x_(2))` SOLUTION :`DeltaH=H_(R)-H_(P)`