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`H_(2)SO_(4)` solution `(80% "by weight and specific gravity" 1.75 g//ml)` is used to prepare `2 litre` of `0.25 MH_(2)SO_(4)` (aq). The volume of `H_(2)SO_(4)` solution (original) which must be used is :A. `107.18ml`B. `43.75ml`C. `35ml`D. None of these |
Answer» Correct Answer - C Let `x ml` of `H_(2)SO_(4)` solution `(n_(H_(2)SO_(4)))_(i) = (n_(H_(2)SO_(4)))_(i)` `1.75x xx (80)/(100) = 2xx0.25` `x = 35 mL` |
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