H_3 C - C -= CH underset(2. CH_3CH_2Br)overset(1. NaNH_2)to A underset(Pd-BaSO_4)overset(H_2)to B

H_3 C - C -= CH underset(2. CH_3CH_2Br)overset(1. NaNH_2)to A underset

1.	H_3 C - C -= CH underset(2. CH_3CH_2Br)overset(1. NaNH_2)to A underset(Pd-BaSO_4)overset(H_2)to B
Answer» A is `H_3C -CH_2 - C -=CH` A is `CH_3 - C -= C-CH_2CH_3` SOLUTION :A is `CH_3 - C -= C-CH_2CH_3`,