1.

`H_(3)C-CH=CH_(2)+HCl` the intermediate of reaction is:A. `CH_(3)-CH-CH_(3)`B. `CH_(3)-CH_(2)CH_(2)`C. `CH_(3)-CH_(-CH_(3)`D. `CH_(3)-CH_(2)-CH_(2)`

Answer» Correct Answer - C
No peroxide effect by HCI,so reaction take place by carbocation.


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