H_3C-undersetunderset(CH_3)|CH-CH=CH_2+HBr to AA (predominantly ) is

1.	H_3C-undersetunderset(CH_3)\|CH-CH=CH_2+HBr to AA (predominantly ) is
Answer» `CH_3-undersetunderset(BR)\|CH-undersetunderset(CH_3)\|CH-CH_3` `CH_3-undersetunderset(CH_3)\|CH-undersetunderset(Br)\|CH-CH_3` `CH_3-undersetunderset(CH_3)\|CH-CH_2-CH_2Br` `CH_3-undersetunderset(CH_3)\|oversetoverset(Br)\|C-CH_2CH_3` SOLUTION :

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