1.

H.C.F. of 36a5b2 and 90a3b4 will be(A) 36a3b2(B) 18a3b2(C) 90a3b4(D) 180a5b4

Answer»

Answer is (B) 18a3b2

36a5b2 = 3 × 3 × 2 × 2 × a5 × b2

90a3b4 = 3 × 3 × 2 × 5 × a3 × b4 

= 3 × 3 × 2 × a3 × b2

H.C.F. = 18a3b2



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