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1. |
H.C.F of $\frac{2}{3}$ , $\frac{4}{5}$, and $\frac{6}{7}$ is :1). $\frac{48}{105}$2). $\frac{2}{105}$3). $\frac{1}{105}$4). $\frac{24}{105}$ |
Answer» RIGHT ANSWER is $\FRAC{2}{105}$ | |