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`H^(+)` ions are in excited state from where maximum 6 types of photons can be emitted. If E is the separation energy of electron in this excited state of `H^(+)` ion, then how many times of energy E is required to ionize Hydrogen atom ? |
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Answer» Correct Answer - 4 `6=(n(n-1))/(2)" "n=4` Separation energy, `E=+13.6 xx(z^(2))/(n^(2))=+13.6xx((2)^(2))/((4)^(2))=3.4 eV` l.E. of Hydrogen atom `=x xxE=13.6 eV` `x=(13.6)/(E)=4` |
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