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`[H^(+)]` of `0.02 NCH_(3) COOH` which is `4%` dissociated, isA. `0.08M`B. `0.12 M`C. `0.008M`D. `0.8M` |
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Answer» Correct Answer - C `alpha = 4% =(4)/(100) = 0.04`, Normality `=0.2` `:. [H^(+)] = alpha xx N = 0.04 xx 0.2 = 0.008M` |
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