1.

h(x) is increasing for x in

Answer»

`(-(pi)/(4),(pi)/(4))`
`(-(pi)/(2),-(pi)/(4))uu(pi)/(4),(pi)/(2))`
`(-(pi)/(4),0)uu(pi)/(4),(pi)/(2))`
`(-(pi)/(2),-(pi)/(4))uu(0,(pi)/(4))`

Solution :h(x) is increasing `rArr h'(x)GT0`
CASE I
`{:("(i) "sin 2x gt0 rArr x in (0,(pi)/(2))),("(ii) "f'(sin^(2)x)gtf'(cos^(2)x) rArr tan^(2)x GT1):}}rArr x in ((pi)/(4),(pi)/(2))`
Case II
`{:(" (i)" sin2xlt0 rArr x in (-(pi)/(2)","0)),(" (ii)"f'(sin^(2)x)gtf'(cos^(2)x) rArr tan^(2)xgt1):}}rArr x in ((-pi)/(2),-(pi)/(4))`


Discussion

No Comment Found

Related InterviewSolutions