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Half life of a radioactive sample is `2x` years. What fraction of this sample will remain undecayed after `x` years?A. `(1)/(2)`B. `(1)/(sqrt(2))`C. `(1)/(sqrt(3))`D. 2 |
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Answer» Correct Answer - b `lambda = (2.303)/(t) log ((N_(0))/(N))` `(0.693)/(t_(1//2)) = (2.303)/(t) log_(10) ((N_(0))/(N))` `(0.639)/(2x) = (2.303)/(x) log_(10) ((N_(0))/(N))` `(1)/(2) log_(10) 2 = log ((N_(0))/(N))` `(N)/(N_(0)) = (1)/(sqrt(2))` Fraction undecayed `= (1)/(sqrt(2))` |
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