1.

Half life period of a first order reaction is 100 min. After 144.3 min concentration of the reactant is reduced to of the original concentration

Answer»

`1//e`
`1//e^(2)`
`10%`
`20%`

Solution :`T_(AV)=1.443, T_(50)=1.443xx100` MIN
= 1443 min
After ONE `T_(av)` CONCENTRATION of the reactant left is 1/e of the original concentration.


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