Halima, Zainab, Farouk and Aminashared sweets as follows: Halimagot 6r

1.	Halima, Zainab, Farouk and Aminashared sweets as follows: Halimagot 6r sweets, which was threetimes as many as Zainab's. Aminagot 6 more sweets than Zainab.Farouk got half as many sweetsas Amina. If they got a total of31 sweets, how many sweets didFarouk get?A. 12C. 1010.B. 4D. 5
Answer» Halima got sweets = 6xZainab got sweets = 6x/3 = 2xAmina got sweets = 2x + 6Farouk got sweets = 2(x + 3)/2= x + 3 As per given condition6x + 2x + (2x + 6) + (x + 3) = 3111x = 31 - 911x = 22x = 22/11 = 2 Therefore Farouk got sweets= x + 3 = 2 + 3 = 5 (D) is correct option

Halima, Zainab, Farouk and Aminashared sweets as follows: Halimagot 6r sweets, which was threetimes as many as Zainab's. Aminagot 6 more sweets than Zainab.Farouk got half as many sweetsas Amina. If they got a total of31 sweets, how many sweets didFarouk get?A. 12C. 1010.B. 4D. 5

Answer»

Halima got sweets = 6xZainab got sweets = 6x/3 = 2xAmina got sweets = 2x + 6Farouk got sweets = 2(x + 3)/2= x + 3

As per given condition6x + 2x + (2x + 6) + (x + 3) = 3111x = 31 - 911x = 22x = 22/11 = 2

Therefore Farouk got sweets= x + 3 = 2 + 3 = 5

(D) is correct option