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Answer» Step-by-step EXPLANATION:Given : cosecθ−sinθ=a3 and secθ−cosθ=b3⇒sinθ1−sinθ=a3⇒sinθcos2θ=a3⇒a=(sinθcos2θ)31Similarly ; b=(cosθsin2θ)31⇒a2b2(a2+b2)=a4b2+a2b4⇒(sinθcos2θ)34(cosθsin2θ)PLEASE MARK me as a BRILLIANT please mark me |
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