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Harihar kaka path dwara lekhak ne sanyukt parivar ke bare me jo kuch bataya hai kya aap usse sehmat hai? Apna tark dijiyeNo spamm pls , it's of 5marks​

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Answer❣

QUESTION :

An object TRAVELS 20m in 4S and then other 20m in 10s . What is the average speed of the object ?

Solution :

As per the question we have two cases so let's ASSUME each as Case 1 and Case 2 respectively !

Case 1 :

Distance Covered : 20m

Time taken : 4 sec

Speed : Distance / time

: 20 / 4

: 5 m / sec

Case 2 :

Distance Covered : 20 m

Time taken : 10 sec

Speed : Distance / time

: 20 / 10

: 2 m / sec

huge average speed = total distance total time

averagespeed=totaltimetotaldistance

= \5 + 2 4 + 10=4+105+2

= 7 40 = 0.175=407=0.175

Hence , the average speed of the object is 0.175 m / sec !!


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