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HBr and HI can reduce sulphurie acid, HCI can reduced `KMnO_(4)` and HF can reduce…………….A. `H_2SO_4`B. `KMnO_4`C. `K_2Cr_2O_7`D. None of the above

Answer» Correct Answer - D
Conc. `H_2SO_4` can oxidise HBr (or HI) to `Br_2` (or `I_2`). `KMnO_4//H^(+)` can oxidise HCl to `Cl_2`. However chemical oxidation of HF to `F_2` is not possible. This is because, fluorine has the highest reduction potential.


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