HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respective

1.	HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respectively. If one number is ‘1 – b2/a2’, then find another number.1. a22. a2 – b3. a4. ab
Answer» Correct Answer - Option 1 : a² GIVEN: HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respectively. One number = (1 – b²/a²) CALCULATION: We know that : HCF × LCM = First number × Second number (a – b) × (a + b) = [1 – (b²/a²)] × Second number Second number = [(a – b) (a + b)]/[1 – (b²/a²)] Second number = (a² – b²)/[(a² – b²)/a²)] Second number = a²

HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respectively. If one number is ‘1 – b2/a2’, then find another number.1. a22. a2 – b3. a4. ab

Answer» Correct Answer - Option 1 : a²

GIVEN:

HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respectively.

One number = (1 – b²/a²)

CALCULATION:

We know that :

HCF × LCM = First number × Second number

(a – b) × (a + b) = [1 – (b²/a²)] × Second number

Second number = [(a – b) (a + b)]/[1 – (b²/a²)]

Second number = (a² – b²)/[(a² – b²)/a²)]

Second number = a²

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HCF and LCM of two numbers is ‘a – b’ and ‘a + b’ respectively. If one number is ‘1 – b2/a2’, then find another number.1. a22. a2 – b3. a4. ab

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