HCl is produced in the stomach which can be neutralised by Mg(OH)_2 in the form of milk of magnesia. How much Mg(OH)_2 is required to neutralise one mole of stomach acid?

HCl is produced in the stomach which can be neutralised by Mg(OH)_2 in

1.	HCl is produced in the stomach which can be neutralised by Mg(OH)_2 in the form of milk of magnesia. How much Mg(OH)_2 is required to neutralise one mole of stomach acid?
Answer» 29.16 g 34.3 g 58.33 g 68.66g Solution :`Mg(OH)_2+2HCl to MgCl_2 + 2H_2O` No. of moles of `Mg(OH)_2` REQUIRED for 2 moles of HCL = 1 No. of moles of `Mg(OH)_2` required for 1 mole of HCl = 0.5 MASS of 0.5 mol of `Mg(OH)_2=58.33xx0.5=29.16g`