He atom can be excited to 1s^(1) 2p^(1) by lambda=58.44nm. If lowest excited state for He lies 4857cm^(-1) below the above. Calculate the energy for the lower excitation state.

He atom can be excited to 1s^(1) 2p^(1) by lambda=58.44nm. If lowest e

1.	He atom can be excited to 1s^(1) 2p^(1) by lambda=58.44nm. If lowest excited state for He lies 4857cm^(-1) below the above. Calculate the energy for the lower excitation state.
Answer» ANSWER :`3.3xx10^(-18)J`