1.

Heat absorbed by the gas undergo a cylic process along closed path in one complete cycle as shown in figure will be _____J.

Answer»

`10^7pi`
`10^4 pi`
`10^2 pi`
`10^(-3)pi`

Solution :For CYCLIC PROCESS `DeltaU=0`
Heat change for a system `DELTAQ=DeltaU+DeltaW`
`DeltaQ=DeltaU+Delta(PV)`
`therefore DeltaQ` = Area under the graph,
`=pir^2kPaxx"lit"`
`=pi((30-10)/2)^2` kPa x lit
`=pi(20/2)^@ kP_a xx "lit"`
`=pixx100xx10^3xx10^(-3)` J
`=100piJ=10^2 piJ`


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