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Heat is considered as a path function, but in an endothermic process , the heat absorbed by the system undercertain specific conditions is independent of path. What are those conditions ? |
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Answer» Solution :Heat BECOME INDEPENDENT of the path , at constant volume and constant pressure. (i) At constant Volume : By I law of THERMODYNAMICS, `DeltaU=Q+w` or `q = DeltaU-W`. Sine `W=-PDeltaV` therefore , `q=DeltaU+PDeltaV` . But as volume remains constant, `DeltaV=0` `:.qv=DeltaU` Since `DeltaU` is a state FUNCTION , therefore qv is also state function. (ii) At constant pressure : `qp=DeltaU+PDeltaV` But `DeltaM=DeltaU+PDeltaV` `DeltaU=DeltaH-PDeltaV` `q_(p)=DeltaH-PcancelDeltaV+PcancelDeltaV` `:'qv=DeltaU` since `DeltaH` is a state function , therefore `q_(p)` is a state function. |
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