1.

Heat is considered as a path function, but in an endothermic process , the heat absorbed by the system undercertain specific conditions is independent of path. What are those conditions ?

Answer»

Solution :Heat BECOME INDEPENDENT of the path , at constant volume and constant pressure.
(i) At constant Volume :
By I law of THERMODYNAMICS, `DeltaU=Q+w` or `q = DeltaU-W`. Sine `W=-PDeltaV` therefore , `q=DeltaU+PDeltaV` . But as volume remains constant, `DeltaV=0`
`:.qv=DeltaU`
Since `DeltaU` is a state FUNCTION , therefore qv is also state function.
(ii) At constant pressure :
`qp=DeltaU+PDeltaV`
But `DeltaM=DeltaU+PDeltaV`
`DeltaU=DeltaH-PDeltaV`
`q_(p)=DeltaH-PcancelDeltaV+PcancelDeltaV`
`:'qv=DeltaU`
since `DeltaH` is a state function , therefore `q_(p)` is a state function.


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