Heat liberated when 100 ml of 1N NaOH is neutralized by 300 ml of 1N H

1.	Heat liberated when 100 ml of 1N NaOH is neutralized by 300 ml of 1N HCl ____
Answer» SOLUTION :BASE =`V_1`= 100 ml `N_1=1N` Acid = `N_2`=300 ml `N_2`=1N Enthalpy of neutralization of 1000 ml =57.3 KJ `therefore` Enthalpy of neutralization of 100 ml =`(57.3 kJ)/1000xx100`= 5.73 kJ

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