Heat of dissociationof aceticacidis 0.30 kcalmol^(-1) . Hence,enthalpy change when 1 molofCa(OH)_(2) is completelyneutralized by aceticacid would be

Heat of dissociationof aceticacidis 0.30 kcalmol^(-1) . Hence,enthalpy

1.	Heat of dissociationof aceticacidis 0.30 kcalmol^(-1) . Hence,enthalpy change when 1 molofCa(OH)_(2) is completelyneutralized by aceticacid would be
Answer» `-13.4 kcal` `-27.1 kcal` `-26.8 kcal` `-27.4 kcal` Solution :`Ca(OH)_(2) rarr Ca^(2+) + 2OH^(-) , i.e., 1` MOLE of`Ca(OH)_(2)` gives two moles of `OH^(-)` ions. HENCE, when `Ca(OH)_(2)` is COMPLETELY neutralized,heat produced `= 2 xx 13.7 kcal = 27.4 kcal` 2 moles of `OH^(-)` ions require 2 moles of `H^(+)` ions for complete neutralization. Heat of dissociation of acetic acidto produce 2 moles of`H^(+)` ions `= 2 xx 0.30 kcal = 0.6 kcal`. Hence, net heat produced `=27.4 - 0.6 =26.8 kcal, i.e., DeltaH =- 26.8 kcal`