1.

Heat of solution and heat of hydration of AgF are -20.5kJmol-1 and -930kJmol-1 respectively. Calculate lattice energy of AgF.

Answer»

Given : Heat of solution of AgF = ΔsolnH

= -ΔH1 = -20.5 kJmol-1

Heat of hydration of AgF = ΔhydH = ΔH2

= -930 kJ mol-1

Lattice energy of AgF = ΔLH = ΔH3 = ?

For heat of solution,

AgF(s) + aq → AgF(aq) ΔH1

For heat of hydration,

Ag+(g) + F-(g) + aq → Ag+(aq) + F-(aq)ΔH2

For Lattice energy,

Ag+(g) + F-(g) → AgF(s)

ΔLH = ?

From above equations,

∴ ΔH3 = ΔH2 – ΔH1

= -930 – (-20.5)

= -909.5 kJmol-1

∴ Lattice energy of AgF(s) = -909.5 kJ mol-1



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