1.

Heats of combustion of garphite carbon and carbon monoxide are respectively -393.5 KJ mol^(-1) and -110.5 "mol"^(-1). Then determine the bond enthalpies.

Answer»

Solution :`C_(("graphite"))+O_(2)(g) to Co_(2)(g):DeltaH=-393.5KJ....(1)`
`CO_((g))+ 1/2O_(2)(g) to CO_(2)(g) , DeltaH=-110.5KJ....(2)`
EQUATION (1) - equation (2) ,gives
`c_(("graphite"))+1/2O_(2)(g) to Co_((g)),DeltaH=-283KJ`
The HEAT of FORMATION of carbon monoixde =-392.5-(-110.5)=-283KJ `mol^(-1)`.
Thermochemical equation,`c_(("graphite"))+1/2O_(2)(g) to Co_((g)),DeltaH=-283KJ`.


Discussion

No Comment Found