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help guys Solve: 1. A solution contains 30g of common salt in 240g of water. Calculate the concentration in terms of mass by mass percentage of the solution. 2.Calulate the mass of the sodium sulphate required to prepare its 30% (mass percent)solution in 200 grams of water. 3.Teacher asked students to prepare a 20% solution (Mass/Mass) of sugar in water. Ramesh dissoved 20g of sugar in 100g of water while Sara prepared it by dissolving 20g of sugar in water to make 100g of the solution. a)Are two solutions of the same concentration? b)Compare the mass % of the two solutions. |
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Answer» Answer: This is your answer... Explanation: 1. CONCENTRATION of solution = mass of solute / mass of solution Mass of common salt is 30g . Mass of water is 240g . Mass of solution = 30 + 240 = 270G Concentration of solution = (30 / 300) * 100 Concentration = 30% 2. Mass of the solution = mass of solute + mass of solvent Given that the mass percent of sodium sulphate solution is 30%. Let the mass of sodium sulphate which is required to prepare this solution be x grams. Given that the mass of water is 200 g. So, 30 = [x/(x + 100)] * 100 30/100 = [x/(x + 100)] 3/10 = [x/(x + 100)] x = (3/10) x (x+100) x = (3x + 300) / 10 3x + 300 = 10x 10x - 3x = 300 7x = 300 x = 42.8 Thus, 42.8 g of sodium sulphate is required. 3. a) No, both are different. b) According to the solution prepared by Ramesh, Mass of sugar he TOOK (Solute) = 20 g Mass of water he took (Solvent) = 100 g Thus Mass % of the solution = mass of solute / mass of solution = (20 / 120) * 100 = 50 / 3 = 16.66 % According to the solution prepared by Sara, Mass of sugar she took (Solute) = 20 g Mass of Solution she took = 100 g Thus Mass % of the solution = mass of solute / mass of solution = (20 / 100) * 100 = 20 % PLEASE MARK AS BRAINLIEST IF IT REALLY HELPS YOU...❣❣❣ |
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