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Hematitic `(Fe_(2) O_(3))` is an important ore of iron. The free metal `(Fe)` is obtained by reducing hematite with carbon monoxide `(CO)` in a blast furnace: `Fe_(2)O_(3)(s) + 3CO(g) rarr 2Fe(s) + 3CO_(2) (g)` How many grams of `Fe` can be produced from `1.00 kg` `Fe_(2) O_(3)` ?A. `698 g`B. `786 g`C. `896 g`D. `968 g`

Answer» Correct Answer - A
Mass of `Fe_(2) O_(3) rarr` Moles of `Fe_(2) O_(3) rarr` Moles of `Fe rarr` Mass of `Fe`
`1.00xx10^(3)g Fe_(2) O_(3) xx (1 mol Fe_(2) O_(3))/(160g Fe_(2) O_(3)) xx (2 mol Fe)/(1 mol Fe_(2) O_(3))`
`xx (55.8g Fe)/(1 mol Fe) = 698g Fe`


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