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Henry's law constant for dissolution of CH4 inbenzene at 298 K is 2 x 105 mm of Hg. Thensolubility of CH4 in benzene at 298 K under760 mm of Hg is:(1) 1.2 x105(3) 4 x10-78.(2) 3.8 x10-3(4) 1 x10-2 |
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Answer» According to Henry's law, p = kH x760 = 2 × 10⁵ × x x = 760/2 × 10⁵ = 3.8 × 10⁻³ is mole fraction solubility Are you asking what is mole fraction solubility? mole fraction solubility = (number of moles of solute)/(number of moles of solute + number of moles of solvent) |
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