Henry's law constant for solubility of methane In benzene is4.2xx 10^(-5) mm Hg at a particular constant temperature At this temperature calculate the solubility of methane at (i) 750 mm Hg (ii) 840 mm Hg

Henry's law constant for solubility of methane In benzene is4.2xx 10^(

1.	Henry's law constant for solubility of methane In benzene is4.2xx 10^(-5) mm Hg at a particular constant temperature At this temperature calculate the solubility of methane at (i) 750 mm Hg (ii) 840 mm Hg
Answer» Solution :`(K _(H))_("BENZENE")= 4.2 xx 10 ^(5) MM Hg,` Solubility of mehhane = ? P = 750 mm Hg. P = 840 mm Hg According to Henry.s Law. `P = K _(11) X _("solution")` 750 mm Hg `= 4.2 xx 10 ^(-5) mm HG . x _("solution")` `implies x _("solution") = (750)/( 4.2 xx 10 ^(-5))` i.e., solubility `= 178.5 xx 10 ^(5)` Similary at `P = 840 mm Hg` Solubility `= (840)/( 4.2 xx 10 ^(-5)) = 200 xx 10 ^(-5)`