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Here we can consider the starting point as A and while the object moves from A to B the displacement is considered to be positive and from B to A it is negative. Answer the following questions: Subha goes to the nearby playground from her home(a) Change in speed(b) Change in direction(c) Change in both speed and directionThe distance travelled by trainInitial velocity (u) m/sFinal velocity (v) m/sChange in velocity (v-u) m/sTime taken (t) sAcceleration = Change in velocity/ time a = (v-u)/1 ms2A-B066100.6B-CC-DD-EE-FThe velocity at different times of a train departing direction is given in the figure. Analyse this and complete the table .

Answer»
The distance travelled by trainInitial velocity (u) m/sFinal velocity (v) m/sChange in velocity (v-u) m/sTime taken (t) sAcceleration = Change in velocity/ time a = (v-u)/1 ms2
A-B066100.6
B-C61414-6 = 8100.8
C-D141414-14 = 0100
D-E1466-14 = 810-0.8
E-F622-6 = -410-0.4


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