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Hex-2-en-4ynioic acid is :A. `CH_(3)-C-=C-CH_(2)-CH=CH-overset(O)overset(||)(C )-OH`B. `HC-=C-CH_(2)-CH=CH-overset(O)overset(||)(C )-OH`C. `CH_(3)-C-=C-CH=CH-CH_(2)-overset(O)overset(||)(C )-OH`D. `CH_(3)-C-=C-CH=CH-overset(O)overset(||)(C )-OH` |
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Answer» Correct Answer - D Hex-2-en-4-ynoic acid is ………….. `underset(6)(C )H_(3)-underset(5)(C )-=underset(4)(C )-underset(3)(C )=underset(2)(C )-overset(O)overset(||)underset(1)(C )-OH` Hex-2-en-4-ynoic acid |
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