1.

HgCl_2` and `SmCl_2` cannot exist together in an aqeous solution . Explain.

Answer» `Sn Cl_2` is a strong reducing agent and hence reduces `HeCl_2` first to `HgCl_2` ( white ) and then to `Hg` ( black ). Hence , these do not exist together .
`SnCl_2 2 hgCl_2 rarr SnCl_4 + Hg_2Cl_2`
`SnCl_2 + Hg_2Cl_2 rarr SnCl_4 +Hg`.


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