HgO is analysed by reaction with iodide and them titrating with an acid. The equivalent mass of HgO is H_(2)O+HgO+4I^(-)rarrHgI_(4)^(-2)+2OH^(-)

HgO is analysed by reaction with iodide and them titrating with an aci

1.	HgO is analysed by reaction with iodide and them titrating with an acid. The equivalent mass of HgO is H_(2)O+HgO+4I^(-)rarrHgI_(4)^(-2)+2OH^(-)
Answer» M M/2 M/4 M/3 Solution :`E=(M)/(n-f)` `HG^(+2)rarrHg^(+2)` hence TREATING it as a salt, `n-f=2`