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HI can not be prepared by heating Nal with concentrated `H_2SO_4`. Give the method which is preferred for the preparation of HI. |
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Answer» Correct Answer - `HI` is a strong reducing agent and, therefore, reduces `H_(2)SO_(4)` to `SO_(2)` and itself get oxidised to `I_(2)`. `3NaI+H_(3)PO_(4)toK_(3)PO_(4) + HI` |
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