1.

HI can not be prepared by heating Nal with concentrated `H_2SO_4`. Give the method which is preferred for the preparation of HI.

Answer» Correct Answer - `HI` is a strong reducing agent and, therefore, reduces `H_(2)SO_(4)` to `SO_(2)` and itself get oxidised to `I_(2)`.
`3NaI+H_(3)PO_(4)toK_(3)PO_(4) + HI`


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