Higher the amount of acid or base used to product a deinite change of pH in a buffer solution, higher will be its buffe capacity. Buffer capcity of solution is maximum under the following conditions [Salt] = [Acid](in acid buffer) [Salt] = [Base] (in base capacity] pH of buffer solution lies inthe range given below `pH = pH_(a) +-1` In other words,any buffer solution can be used as buffer up to two pH units only, depending upon the value of `pK_(a)` or `pK_(b)`. A buffer is said to be efficient when `pH = pK_(a)` or `pOH = pK_(b)` A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution `(Q_(sp))` becomes greater than its solubility product. If the solubility of `BaSO_(4)` in water is `8 xx 10^(-4) "mol" dm^(-3)` calculate its solubility in `0.01 "mol" dm^(-3)` of `H_(2)SO_(4)`A. `6 xx 10^(-5)`B. `5 xx 10^(-3)`C. `2 xx 10^(-3)`D. `6 xx 10^(-8)`

Higher the amount of acid or base used to product a deinite change of

1.	Higher the amount of acid or base used to product a deinite change of pH in a buffer solution, higher will be its buffe capacity. Buffer capcity of solution is maximum under the following conditions [Salt] = [Acid](in acid buffer) [Salt] = [Base] (in base capacity] pH of buffer solution lies inthe range given below `pH = pH_(a) +-1` In other words,any buffer solution can be used as buffer up to two pH units only, depending upon the value of `pK_(a)` or `pK_(b)`. A buffer is said to be efficient when `pH = pK_(a)` or `pOH = pK_(b)` A sparingly soluble salt gets precipitated only when the product of concentration of its ions in the solution `(Q_(sp))` becomes greater than its solubility product. If the solubility of `BaSO_(4)` in water is `8 xx 10^(-4) "mol" dm^(-3)` calculate its solubility in `0.01 "mol" dm^(-3)` of `H_(2)SO_(4)`A. `6 xx 10^(-5)`B. `5 xx 10^(-3)`C. `2 xx 10^(-3)`D. `6 xx 10^(-8)`
Answer» Correct Answer - A `K_(sp) = 64 xx 10^(-8)` `K_(sp) = (S) (S + 0.01)`

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