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हल कीजिए `"tan"^(-1)(x+1)+"tan"^(-1)(x-1)="tan"^(-1)8/31` |
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Answer» `"tan"^(-1)(x+1)+"tan"^(-1)(x-1)="tan"^(-1)8/31` `"tan"^(-1)(x+1+x-1)/(1-(x+1)(x-1))="tan"^(-1)8/31` `(2x)/(1-x^(2)+1)=8/31` `x/(2-x^(2))=4/31` `31x=8-4x^(2)` `4x^(2)+31x-8=0` `4x^(2)+32x-x-8=0` `4x(x+8)-1(x+8)=0` `(x+8)(4x-1)=0` `x=-8, 1/4` |
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