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How are 0.5 mol Na2CO3 and 0.5 M Na2CO3 different? |
Answer» Molar mass of\xa0Na2CO3\xa0= (2×23)+12.00+(3×16)\xa0= 106\xa0g mol-1∴0.50 mol Na2CO3\xa0means 0.50×106g = 53g0.50 M Na2CO3\xa0means 0.50 mol of\xa0Na2CO3\xa0i.e. 53g of\xa0\xa0Na2CO3\xa0are present in 1litre of the solution. | |