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How are 0.50 mol Na_(2)CO_(3) and 0.50 M Na_(2)CO_(3) different ?

Answer»



Solution :Atomic MASS of `Na_(2)CO_(3)`
`= (2 xx 22.99) + 12.01 + (3 xx 16)`
`= 105.99 ~~ 106` gm/mole
0.5 mole `Na_(2)CO_(3) = 0.5 xx 106`
`= 53 gm Na_(2)CO_(3)`
So, 0.5 mole `Na_(2)CO_(3)` MEANS 53 gm `Na_(2)CO_(3)` present in 1 litre solution.


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