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How are 0.50 mol Na_(2)CO_(3) and 0.50 M Na_(2)CO_(3) different ? |
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Answer» `= (2 xx 22.99) + 12.01 + (3 xx 16)` `= 105.99 ~~ 106` gm/mole 0.5 mole `Na_(2)CO_(3) = 0.5 xx 106` `= 53 gm Na_(2)CO_(3)` So, 0.5 mole `Na_(2)CO_(3)` MEANS 53 gm `Na_(2)CO_(3)` present in 1 litre solution. |
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