1.

How does a pure (an ideal) capacitor behave when the frequency of the applied alternating emf is very low?

Answer»

Capacitive reactance = \(\cfrac{1}{2\pi fc}\)

If the frequency (f) of the applied emf is very low, the capacitive reactance (for reasonable value of capacitance C) will be very high and hence the current through the circuit will be very low (for reasonable value of peak emf).



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