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How does `Cu_(2)O` act as both oxidant and reductant ? |
Answer» `Cu^(+)` undergoes disproportionation to form `Cu^(2+)` and Cu. `2Cu^(+) (aq) to Cu^(2+) (aq) + Cu(s)` Thus, `Cu^(+)` or `Cu_(2)O` acts both as an oxidant and a reductant |
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