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How does Cu_(2)O acts as both oxidant and reductant ? Explain with proper reaction showing the change of oxidation number in each example |
Answer» Solution :`Cu^(+)` undergoes disproportination to form `Cu^(2+)` and Cu  Here `Cu^(2+) to Cu^(2+) therefore Cu^(+)` ACTS an OXIDANT Again `Cu^(+) "reduces" Cu^(+) "to" Cu therefore Cu^(+)` acts as a reductant THUS `Cu^(+) or Cu_(2)O` acts both as an oxidatn as well as a reductant (i)`Cu_(2)O` acts in AIR `Cu_(2)O` is oxidised to `CuO,Cu_(2)O + 1//2 O_(2) rarr 2CuO` (ii) When HEATED with `Cu_(2)S` it oxidises `S^(2-)` to `SO_(2)` and hence `Cu_(2)O` acts as an oxidant `2 Cu_(2)O+Cu_(2) rarr 6Cu+SO_(2)` |
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