1.

How does Cu_2O act as both oxidant and redcutant ? Explain with proper reactions showing the change of oxidation number in each case.

Answer»

Solution :In `Cu_2O` , COPPER is in +1 `(CU^(+))` oxidation state and it undergoes disproportionation to form `Cu and Cu^(2+)` as :
`2Cu^(+)(aq)rarrCu(s)+Cu^(2+)(aq)`
THUS, `Cu^(+) ` or `Cu_2O` acts both as an oxidant as WELL as a reluctant.
For example,
(i) When HEATED in air , `Cu_2O` is oxidised to CuO.
`overset(+1"")(Cu_2O)+1/2O_2rarroverset(+2"")(2CuO)`
Thus, `Cu_2O` acts as a reluctant and reduces `O_2` to `O^(2-)`.
(ii) When heated with `Cu_2S` , it oxidises `S^(2-) " to " SO_2` and hence `Cu_2O` acts as an oxidant.
`overset(+1"")(2Cu_2O)+overset(+1"")(Cu_2S)rarroverset(0"")(6Cu)+SO_2`


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