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1. |
How does hydrogen peroxide behave in the reaction with `KIO_(4)` |
Answer» In this reaction, oxidation state of I decreases from +7 to +5. Therefore, it is gets reduced. This means `H_(2)O_(2)` acts as an oxidising agent `overset(+7)(KIO_(4))+H_(2)O_(2) to overset(+5)(KIO_(3))+H_(2)O+O_(2)` |
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