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How does the effect of the process C_(2) to C_(2)^(+) + e^(-) affect the bond order ? |
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Answer» Solution :`C_(2)^(+) : (sigma_(1s))^(2)(sigma_(1s)^(**))^(2) (sigma_(2s))^(2) (sigma_(2s)^(**))^(2) (pi_(2)p_(X))^(2) = (pi_(2)p_(y))^(1)` Bondorder ` = 1/2 (8 - 4) = 2` `C_(2)^(+) : (sigma_(1s))^(2) (sigma_(1s)^(**))^(2) (sigma_(2s))^(2)(sigma_(2s)^(**))^(2) (pi_(2)p_(x))^(2) = (pi_(2)p_(y))^(1)` BOND ORDER ` = 1/2 (7 - 4) = 1.5` ` :. ` The Bond order DECREASES by `1.5` during the process. |
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