1.

How does the fringe width of interference fringes change, when the whole apparatus of Young’s experiment is kept in a liquid of refractive index 1.3?

Answer»

Fringe width, β = Dλ/d => β ∝  λ  for same D and d. When the whole apparatus is immersed in a  transparent liquid of refractive index n =1×3, the wavelength decreases to   λ = λ/n = λ/1.3. so, fringe width decreases to 1/1.3 time.



Discussion

No Comment Found

Related InterviewSolutions